1=(2)/(x^2)-(x-1)/(x+1)

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Solution for 1=(2)/(x^2)-(x-1)/(x+1) equation: 


D( x )

x+1 = 0

x^2 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:-1) U (-1:0) U (0:+oo)

t_1 = 1

(x-1)/(x+1)+t_1-2*x^-2 = 0

(x-1)/(x+1)+t_1-2/(x^2) = 0

(x^2*(x-1))/(x^2*(x+1))+(t_1*x^2*(x+1))/(x^2*(x+1))+(-2*(x+1))/(x^2*(x+1)) = 0

x^2*(x-1)+t_1*x^2*(x+1)-2*(x+1) = 0

t_1*x^3+t_1*x^2+x^3-x^2-2*x-2 = 0

t_1*x^3+t_1*x^2+x^3-x^2-2*x-2 = 0

t_1*x^3+t_1*x^2+x^3-x^2-2*x-2

x^2*(t_1+x)+t_1*x^3-x^2-2*x-2

x^2*(t_1*x-1)+x^2*(t_1+x)-2*x-2

x^2*(t_1*x-1)-2*(x+1)+x^2*(t_1+x)

x^2*(t_1*x+t_1+x-1)-2*(x+1)

-1*(t_1*x+t_1+x-1)

(-1*(t_1*x+t_1+x-1))/(x^2*(x+1)) = 0

(-1*(t_1*x+t_1+x-1))/(x^2*(x+1)) = 0 // * x^2*(x+1)

-1*(t_1*x+t_1+x-1) = 0

t_1*x+t_1+x-1 = 0

t_1+x-1 = 0 // - t_1-1

x = -(t_1-1)

x = 1-t_1

t_1+x-1 = 0

-1*(t_1+x-1) = 0

t_1+x-1 = 0 // - t_1-1

x = -(t_1-1)

x = 1-t_1

x in { 1-1} 

x belongs to the empty set

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